Can you solve the following? it's about vectors
By lonely_f16
@lonely_f16 (2146)
Philippines
July 17, 2007 7:40am CST
3. Minnie dives off the 4-m springboard and initially bounces up with a velocity of 8 m/s at an angle of 60 degrees to the horizontal. What are the horizontal and vertical components of her velocity?
5.) Bodie wants to go to Galleria which is 60 m 30 degrees North west from his house. How far north and how far west is Galleria from his place?
thanks a lot and hope you could help me...
any method would do like graphical, mathematical or component method...thanks!
1 person likes this
2 responses
@stvasile (7306)
• Romania
16 Sep 07
3. To find out the horizontal component of a vector (velocity in this case), you must multiply the vector's value (8 m/s) with the cosine of the angle that vector makes with the horizontal direction. In this case, 8*cos(60). Cos(60)=1/2, so the horizontal component is 8*1/2=4 m/s.
To get the vertical component, you must multiply the vector's value by the sine of the angle between the vector and the horizontal direction. In your case, 8*sin(60)=8*0.866= approx. 6.93 m/s.
5. It's the same type of problem as in the previous case, only a bit modified.
Only in this case, the horizontal component is how much he must go west and the vertical component how much he has to go north.
So for the western road length: 60*cos(60)=60*1/2=30 m (because if the Gallery is 30 degrees northwest, it makes a 60 degree angle with the west=horizontal direction)
And to see how far he must go north: 60*sin(60)=60*0.866= approx. 51.96 m.
@rowell_marapao (235)
• Philippines
17 Jul 07
wow! you are also from the phillipine?
am i right? its been soo long when i answered one of these vectors.. getay an nako ani!! aheehe
