# 2+2=5

@rupturetissue (114)

India

May 16, 2008 12:43pm CST

hey i can prove that(but with no mathematical way..there is a mathematical error in the solution, try to find it)
u may be familiar with the formula a^2 - b^2(read as (a square) minus (b square))
= (a+b)*(a-b)
now the proof,
10-10 = 0.....eq no. 1
2^2 - 2^2 = 0....eq no. 2
from eq no 1 & 2
10-10 = 2^2 - 2^2
now,
5(2-2) = (2+2)*(2-2)....taking 5 common from the first term and by using the result mentioned above we get this
now cancel the same terms (2-2) from both sides..
finally we get 5 = 2+2 or 2+2 = 5
lets see if u can find the error

2 people like this

2 responses

@panupongsk (313)

• Thailand

16 May 08

Since (2-2) = 0 and you can't cancel 0 from the equation.
Thus, the error occurred from the reason I mentioned above.

@josephperera (2909)

• Sri Lanka

13 Jun 08

The answer has already been given. I can still remember about 35 years ago our maths master saying "Thou shall not divide by zero".
If this is possible then we can prove anything.
For instance 4 x 0 = 28 x 0
Now divide both sides by zero and 4 = 28