No ANSWER for this QUESTION till NOW... ANSWER it PLEASE?

@varuntr (644)
India
October 4, 2006 6:45am CST
there were 3 men a dog and a pack of biscuits on a picnic... in nite... one men wakes up and opens the box of buiscuit and divides in three parts where one bisucut was being left completely which he gives it to the dog (for example 10 bisuits were there. divided in 3 parts gives 3 quotient +1 remainder... remainder goes to the dog)... and the guy eats his part and go to sleep... the other guy wakes up in nite he divides the box of biscuit in three parts were there was one remaining buisuit again which he gives it to the dog and eats his part and goes do sleep ... same was the case with the other,,, in morning the all three wake up.. open the box of buiscuit and divide it on 3 parts where one biscuit was remaining after dividing which was given to the dog... and then they eat there part of biscuits... now the biscuits have ended up.. and there were zero biscuits left in the box.... HOW MANY BISCUITS WERE THERE IN THE BOX AT THE STARTING?????
5 responses
@mythmoh (3994)
• United States
29 Oct 06
wheather my answer is right?
@vidyadas (415)
• India
4 Nov 06
i think u r rt...
@clintz15 (977)
• India
5 Oct 06
Is the answer unique ?
@varuntr (644)
• India
27 Oct 06
no....
• India
1 Dec 06
Good question, I will tellyou the result but will take some time
@mythmoh (3994)
• United States
5 Oct 06
Totally there will be 79 biscuits. After 1st person=3(26)+1 so remaining 52 after 2 person 52=3(17)+1 so remaining 34 after 3 person 34=3(11)+1 remains 22 biscuits 22/3=7 biscuits for each and 1 for dog
• India
4 Oct 06
i dont think this question is so difficult.it is easy to get the answer.just need to apply your mind to it.