Prove this wrong !

@register (1065)
India
October 13, 2006 12:01pm CST
let a = b a² = ab Multiply both sides by a a² + a² - 2ab = ab + a² - 2ab Add (a² - 2ab) to both sides 2(a² - ab) = a² - ab Factor the left, and collect like terms on the right 2 = 1 Divide both sides by (a² - ab)
2 responses
@mnjtrana (14)
• India
22 Oct 06
u r wrong because in step 2(a² - ab) = a² - ab we know a=b a² - ab=0 then anything multiplied by 0 is zero u cannot cancel zero on both sides so 2*0=1*0 i .e. 0=0 so simple
@RAMPersona (2036)
• Philippines
22 Oct 06
This cannot be, unless a² - ab is not equal to 0. If implementing division to prove an equation, it is imperative to specify that the divisor in this case a² - ab does not approach to 0 value or that lead to division by zero.