Algebra  

do u need kpo?

i really hate any forms of mathematics.. i dont have any idea=(

31 + 33 + 35 = 99 < 100

let the 3 numbers be x-2,xand x+2
so x-2+x+x+2=99
3x=99 and x=33
therefore 3 numbers r 31,33,35

Let's see...

Let x = the first odd integer.
Let x + 2 = the second odd integer
Let x + 4 = the third odd integer

x + (x + 2) + (x + 4) < 100
x + x + 2 + x + 4 < 100
3x + 6 < 100
3x + 6 - 6 < 100 - 6
3x < 94
x < 31 1/3 (not an integer so we will need to drop down to 31)

31, 33, and 35 are the numbers.

31 + 33 + 35 = 99
They are consecutive odd integers and their sum is less than 100.

31 33 35 but i see some people had solved it already so i cheated a little lol

Let one odd integer be x,

Then three consecutive odd integers will be x-2, x and x+2

Now let the sum of these three be less then 100 means our ineqality would be

x-2 + x + x + 2 < 100

3x < 100

x < 100/3

x < 33.33

Since we know that 33.33 is not an integer and we want an nearest integer which is odd we will have to consider 33 as the desired odd integer !

Then other two integers will be 31 and 35 !

So the three consecutive integers are 31, 33, 35 and the sum of these is 99 which is less than 100.

it is 31,33,35.