Factorise

Question - Number
@Wulfric (160)
India
June 19, 2007 1:18am CST
Factorise 2a^2*b^2+2b^2*c^2+2c^2*a^2-(a^4+b^4+c^4)
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1 response
• India
26 Jun 07
Let a^2 = x; b^2 = y; c^2 = z; Then your expression is 2xy + 2yz + 2zx - (x^2 + y^2 + z^2) then its value is : -(x + y + z)^2 So the solution is : -(a^2 + b^2 + c^2)^2 Please give me response whether correct or not