May 14, 2008 6:29pm CST
Can u help me with this problem simplify 5x-8y-(x+3)+4(x-2y)
16 May 08
well, I am not good in math but I think I am gonna give it a shot. 5x-8y-(x+3)+4(x-2y)= (x+3)+4(x-2y)-(-(5x-8y)) (x+3)+4(x-2y)-(-(5x-8y))= 5x-8y-(x+3)+4(x-2y) not I think you can add both sides of both equations 5x-8y-(x+3)+4(x-2y)+ (x+3)+4(x-2y)-(-(5x-8y)) = (x+3)+4(x-2y)-(-(5x-8y))+ 5x-8y-(x+3)+4(x-2y) all in all; 0 = 0 so I think it 0. I am not good at math but I think I gave it a good shot. hope this is right. good louck
15 May 08
Oh my goodness. Maths was never my strong point at school, failed my maths exams, and i can't do big numbers!!! good job I don't do the banking in our house!!! I am wondering why you need to know the answer to this maths question?? I hope you are not cheating with your maths homework!!! What do the y's and x's mean anyway?
15 May 08
I guess that's what he was doing :D X and Y are the 'unknown quantities' (or variables, I guess). They're like hidden numbers to find out and when thy're written right next a number it means that it's a multiplication. For example 3x = 12 means that you have to find the number that multiplied for 3 gives 12.
20 May 08
You just have to do some groupings or transposition if it'll help you see the solution better... 5x - (x+3)+ 4(x-2y) = 8y 5x - x - 3 + 4x - 8y = 8y 8x -3 - 8y = 8y 8x - 3 = 16y There's your answer. Learning Algebra is just easy. Some find it difficult, or I guess distracted because of the variables and the positive/negative signs. But dont let it fool you! ('v')
16 May 08
simple first follow the set of BODMAS(bracket operation, division, multiplication, addition, subtraction) so following this we have step 1: bracket operation so we get 5x-8y-x-3+4x-8y step 2: terms of the same type are kept together 5x-x+4x-8y-8y-3 step 3: addition 8x-16y-3