# 2+2=5

India
May 16, 2008 12:43pm CST
hey i can prove that(but with no mathematical way..there is a mathematical error in the solution, try to find it) u may be familiar with the formula a^2 - b^2(read as (a square) minus (b square)) = (a+b)*(a-b) now the proof, 10-10 = 0.....eq no. 1 2^2 - 2^2 = 0....eq no. 2 from eq no 1 & 2 10-10 = 2^2 - 2^2 now, 5(2-2) = (2+2)*(2-2)....taking 5 common from the first term and by using the result mentioned above we get this now cancel the same terms (2-2) from both sides.. finally we get 5 = 2+2 or 2+2 = 5 lets see if u can find the error
2 people like this
2 responses
• Thailand
16 May 08
Since (2-2) = 0 and you can't cancel 0 from the equation. Thus, the error occurred from the reason I mentioned above.
• Sri Lanka
13 Jun 08
The answer has already been given. I can still remember about 35 years ago our maths master saying "Thou shall not divide by zero". If this is possible then we can prove anything. For instance 4 x 0 = 28 x 0 Now divide both sides by zero and 4 = 28 