Balut Question
By agihcam
@agihcam (1914)
Philippines
June 27, 2008 8:40pm CST
I was carrying a basket of Balut. The first buyer bought half of my Balut and asked for another one for free. The next buyer bought half of the remaining half of my Balut and asked for another one for free. The third buyer bought half of the remaining half of my Balut and asked for another one for free. This time, nothing left except my basket, all my Balut was gone.
Can you help me to find how many Balut I have so that after the third buyer I don't have Balut left on my basket? Your answers including the details or formula if possible would be nice. Try it.
2 responses
@koharukusumi (1539)
• Malaysia
28 Jun 08
x = how many baluts you have
1st scenario, 0.5x +1
2nd scenario, 0.5(x-(0.5x+1))+1=0.5(0.5x-1)+1=0.25x+0.5
3rd scenario, 0.5(x-(0.5x+1+0.25x-0.5))+1=0.5(0.25x-1.5)+1=0.125x+0.25
Formula is x-(1st scenario+2nd scenario+3rd scenario) = 0
The answer is 14 i think
@koharukusumi (1539)
• Malaysia
28 Jun 08
x= number of baluts
say number of 1st balut 1st buyer buys,A =0.5x+1
2nd buyer buys,B =0.25x+0.5
3rd buyer buys,C=0.125x+0.25
x-(A+B+C)=0
u will get 0.125x=1.75 and x=14
@dhangski (3194)
• Philippines
28 Jun 08
Ok, here is my answer. You have 14 balut in your basket.
14-(7+1)=6 (first buyer)
6-(3+1)=2 (2nd buyer)
2-(1+1)=0 (3rd buyer)
Check if I'm right. LOL
Happy Solving!!!!
Happy Solving!!!!
