Mathematical/number combination question... please help??
@handsomeitaliano (1050)
United States
December 14, 2008 11:08pm CST
I need some help trying to figure this out. Ok.. let's say we have some 5 digit number combinations that always begin with 1 and the remaining 4 are random, i.e.
1 _ _ _ _
What are the number of ways that those 4 remaining numbers can be randomly selected from a field of 55 numbers?
2 responses
@neuronic (242)
• Japan
23 Dec 08
jabaz, I believe you might be incorrect. This is a matter of permutations where you have field of 55 numbers and you have to randomly choose the 4. Thus making an equation to look something like this:
number of ways = 55!/(55-4)! where n! is factorial (example 4! = 4*3*2*1 = 24)
anyways, from this equation we get that
number of ways = 55*54*53*52 = 8185320
I believe that's the proper solution to your problem.
