Penny stocks

United States
January 27, 2009 4:17pm CST
So does anyone know about any good penny stocks I should research? Right now I'm looking at AMD at 2.08 its a pretty good deal being a old company and I see stock prices normally at like 6 a share and there are some new products coming out soon and the whole partnering and making the foundry. But I want to make see if there are any other stocks that might be good for me to research and worth my time and money not that I have a lot of it but hopefully I will after this.
1 person likes this
3 responses
@LouieWpHs04 (4554)
• United States
29 Jan 09
I think it's best not to invest in any stocks until some sort of stabalization occurs in the stock market, if that happens. If not, start learning survival skills.
• United States
29 Jan 09
True but if you have the money its a great opportunity to get some reliable stocks at really low prices so like the money I make off of this site and other things that I don't spend on anything else I invest in companies that are hopefully reliable and will survive the current down trend. There is always an up and the next one will be pretty big after a fall like this.
@maxsee212 (799)
• United States
26 Mar 09
stay away from penny stocks because they can go down a lot in a trading day, but they could up also. they are very high risk investments, i would not touch them if i were you.
@1fastcat (80)
• United States
21 Feb 09
Normally I would say to avoid penny stocks. They can and do go to zero. There are going to be plenty of bargains out there when the time is right. But you can't just look at a low price and say it is cheap. Some good companies are simply being dragged down with the market but others went way down because they are not good and have real problems. I am not going to give advice on AMD or any other stock. For all I know they might roll outhe next great product and go up 1000%. But you really need to do research to find out which companies have the best chance of rebounding and which one are really going bankrupt and therefore to zero.