Smoking on the Cheap

@taface412 (3175)
United States
October 26, 2009 9:54am CST
I never thought I would come to this as a smoker, but it actually makes sense and if I am giong to smoke I mind as well do it for the cheap. Earlier this year I began rolling my own cigarettes. I did it when the costs began to rise of tobacoo products. ANd I can say it actually is not that hard, more affordable and a way I can actually pay attention to the amount of cigarettes I consume. ANd before anyone gauffs at this think about it....Wouldn't you rather pay .40 cents per pack compared to the $4.95 per pack. That is what it boils down to depending on the brand of tobacco you buy and the initial investment of a good rolling machine. The paper tubes usually cost around two bucks and they make a carton of cigs. ANd to me it is worth the 15-30 minutes of rolling each night while watching tv or talking on the phone in order to save thousands of dollars a year. Like I said, if I am going to smoke why not do it the cheaper way. ANd for those who are brand conscience they do have branded tobacco out there. So anyone else rolling their own?
1 person likes this
2 responses
• United States
28 Oct 09
Rolling your own is a phrase reserved for another kind of cig, but since you stated your point in the beginning I understand what you meant. I guess if you are going to save money you might as well do it yourself. I'm sure you might get some funny looks but its your choice to smoke them. I'm sure you won't be letting anybody bum one off you.
@tdemex (3540)
• United States
26 Oct 09
Not yet but have often thought about it! I have friends that do. I was making a lot of money and it wasn't an issue, but I'm laid off and I'll surely do it if I go back to the states! I'm in Mexico now and their only $2.20 a pack. I'm ok for now! Good Luck and I can see how this is an easy way to monitor your consumption! tdemex
@taface412 (3175)
• United States
26 Oct 09
That's a sweet deal at $2.20. And I do watch how much I actually consume doing it this way. Thansk for the response.