I cant work this out!!
By krusty1
@krusty1 (68)
February 14, 2007 3:16pm CST
Three men go in to a motel, the man behind the desk say's the room will be £30. So each man pays £10 and goes to the room.
A while later the man behind the desk realises the room is only £25 so he sent the bellboy to the three guys room with £5.
On the way the bellboy couldn't figure out how to split £5 evenly between three men, so he gave each man £1 and kept £2 for himself.
This meant that each man paid £9 for the room which is a total of £27 + the £2 that the bellboy kept= £29
Where is the other £1???
1 person likes this
3 responses
@nicolec (2671)
• United States
14 Feb 07
I don't think it works that way. You are not tryint to add to 30 anymore. Look at this way. If the three men paid 9 each, with equals 27, that is 2 more than the 25. The 2 is in the bell boys pocket. You see? You aren't adding to 30, but trying to make 25.
1 person likes this
@Withoutwings (6992)
• United States
14 Feb 07
We did this problem at the start of my statistics class. It really does add up... it just seems like it doesn't.
1 person likes this
@josephperera (2906)
• Sri Lanka
15 Feb 07
I already answered another discussion on this topic. But if you had not seen that then here is the answer again.
This is a case where you are taken on a different track from the answer. The charge of the motel is $25. This is not divisible by 3. This is what the 3 guests should have paid. Then they were given back $3. So that is $3 balance money. So now (25+3) $28 is accounted for. Then the waiter pocketed out $2. So that is $30 (28+2).
