MORE fun puzzles. You asked for more, so try these:
By cloudwatcher
@cloudwatcher (6861)
Australia
January 16, 2007 11:31pm CST
Best reponse to the first one to get them all right.
a "+" to everyone who gets one right
1. You are given a corked bottle with a coin in it. Your task is to remove the coin without removing the cork or breaking the bottle. You cannot drill a hole in the cork or the glass. How will you get the coin out?
2. On a pool table there are 12 balls of identical size, but one ball is slightly heavier than the others, but not enough for you to be able to tell without weighing them.
The person you love has a set of balance scales. If you can tell which is the heavier ball, with only THREE weighings, she will be yours. How can you tell which is the heavy ball?
3. A man is born in 1982. He dies in 1962 aged 35. How is this possible?
2 people like this
6 responses
@Sunayna611 (260)
• India
17 Jan 07
For # 2; First the Balls are divided in 2 sets of 6 Balls each.Now they are weighed on the balance scale. Then the heavier set of 6 balls is selected and further divided in 2 sets of 3 balls each.As earlier these are also weighed and the hevier of the 2 sets is selected.Now out of 3 balls 2 balls are selected randomly and weighed on the balance scale.We'll get if any of these 2 balls is heavier.If both of them weigh equal,the third one is the heavy ball...Hmm I tried this one first because none answered it...
@cloudwatcher (6861)
• Australia
17 Jan 07
Congratulations on number 2.
No, you cannot break the glass, and the bottle wasn't already broken.
@cloudwatcher (6861)
• Australia
18 Jan 07
People DO die younger than that.
The question is to be ready.
So live, that when you come to die,
you have nothing left to do, but die.
@cloudwatcher (6861)
• Australia
17 Jan 07
No, I'm sorry. That would be equivalent to breaking the glass. There is an easier way.
1 person likes this
@rodmac (94)
•
27 Jan 07
Weighing 1:- Four balls v Four balls - if they balance then faulty one is NOT one of them.
Weighing 2:- Three of remaining balls v Three of 'perfect' balls - if they balance then faulty one is still NOT there
Weighing 3:- Remaining One ball v ANY of 'perfect' balls and if this goes higher it is "faulty light" - if it goes lower it is "faulty heavier" - QED
Things become a bit trickier to explain if after Weighing 1 there is a high v low result.
But, basically, you remove three from any Pan and replace them with any three from the table to be ready for Weighing 2... If the pans still don't balance ...
