# Where is the remaining 1$????

@janvee_sweetgirl (49)

India

February 16, 2007 12:41am CST

Three friends went to a hotel. The bill was 75$
Each one contributed 25$
the waiter took the bill to the cashier.
The Cashier was happy & decided to give them a discount of 5$ & ask the waiter to return them 5$
Now the waiter was confused. How to distribute 5$ among 3 persons?
He kept 2$ in his pocket & give one rupee to each one of the 3 persons.
So initially each one had contributed 25$. Now as they are given 1$ back, their contribution reduce to 24$.
They all contributed 24$ that is 24x3=72 & 2$ are in the waiters pocket
The total becomes 74. But they had paid 75$
Where is the remaining 1$???

2 responses

@RAMPersona (2036)

• Philippines

16 Mar 07

this is a trick question. the "remaining 1$" and "rupee to each one" are misleading to the right computation/analysis.
$75 - $1 - $1 - $1 ($1 was sent back to each among friends)
=$72
=3 friends x $24 ($24 is from $25 minus $1 that was sent back..)
then,
$72 - $2 ($2 was kept by the waiter)
=$70 .which should be the bill in the first place if the $5 discount was credited.
"$75 - $5"
?

@tsmeesa98 (576)

• United States

16 Feb 07

By the waiter keeping the $2 then the bill became $72. So then each person got $1 back which = $3 which totals $75.