Where is the remaining 1\$????

India
February 16, 2007 12:41am CST
Three friends went to a hotel. The bill was 75\$ Each one contributed 25\$ the waiter took the bill to the cashier. The Cashier was happy & decided to give them a discount of 5\$ & ask the waiter to return them 5\$ Now the waiter was confused. How to distribute 5\$ among 3 persons? He kept 2\$ in his pocket & give one rupee to each one of the 3 persons. So initially each one had contributed 25\$. Now as they are given 1\$ back, their contribution reduce to 24\$. They all contributed 24\$ that is 24x3=72 & 2\$ are in the waiters pocket The total becomes 74. But they had paid 75\$ Where is the remaining 1\$???
2 responses
@RAMPersona (2036)
• Philippines
16 Mar 07
this is a trick question. the "remaining 1\$" and "rupee to each one" are misleading to the right computation/analysis. \$75 - \$1 - \$1 - \$1 (\$1 was sent back to each among friends) =\$72 =3 friends x \$24 (\$24 is from \$25 minus \$1 that was sent back..) then, \$72 - \$2 (\$2 was kept by the waiter) =\$70 .which should be the bill in the first place if the \$5 discount was credited. "\$75 - \$5" ?
• Philippines
16 Mar 07
the "\$" sign may be replaced by whatever currency.
@tsmeesa98 (576)
• United States
16 Feb 07
By the waiter keeping the \$2 then the bill became \$72. So then each person got \$1 back which = \$3 which totals \$75.