2+2=5  | | hey i can prove that(but with no mathematical way..there is a mathematical error in the solution, try to find it) u may be familiar with the formula a^2 - b^2(read as (a square) minus (b square)) = (a+b)*(a-b) now the proof, 10-10= 0.....eq no. 1 2^2 - 2^2= 0....eq no. 2 from eq no 1 & 2 10-10= 2^2 - 2^2 now, 5(2-2)= (2+2)*(2-2)....taking 5 common from the first term and by using the result mentioned above we get this now cancel the same terms (2-2) from both sides.. finally we get 5= 2+2 or 2+2= 5 lets see if u can find the error
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| | | | | | 1. panupongsk (267) | 3 months ago | Since (2-2)= 0 and you can't cancel 0 from the equation. Thus, the error occurred from the reason I mentioned above.
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goergineo (768) | 3 months ago | good one. I like it
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| sam_wise (68) | 3 months ago | This is also known as the "divide by zero" error.
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| | 2. josephperera (2383) | 1 month ago | The answer has already been given. I can still remember about 35 years ago our maths master saying "Thou shall not divide by zero". If this is possible then we can prove anything. For instance 4 x 0= 28 x 0 Now divide both sides by zero and 4= 28
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