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Physics (circular motion)?

6 years ago

There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted so that it can be rotated about its axis by turning a hand crank. The outer wall of the cylinder is perforated with small holes. You put the wet leaves in the container and turn the crank to spin the water. The radius of the container is 12 cm. When the cylinder is rotating at 2.0 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?

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1. prototaip (34)

6 years ago

centripetal acceleration=radius X (angular velocity)²
=radius X (frequency X 2 X pi)²
=12 cm X (2/s X 2 X pi)²
=0.12 m X (4 X 3.142)²
=18.95 m/s²
=18.95 meter per second second
If my answer is wrong,correct me and show the real calculation.

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2. ebrahimebram (62)

6 years ago

W=2 times pie times frequency
acceleration equals to omega square times radius
the acceleration is 18.9

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